如何拒绝同学抄作业

函数y=log2[(a²-1)x²+(a-1)x+1]的定义域为R,则a的取值范围是函数y=log2[(a²-1)x²+(a-1)x+1]的值域为R,则a的取值范围是 when i call you this morning,nobody answer the phone. where____? 答案填were you,为什么...when i call you this morning,nobody answer the phone. where____? 答案填were you,为什么不可以写did you go.? No one answered when I phoned this morning.Where were you?—I for teeth in the dental clinicA.was being treated B.have been treated C.was treated D.treated解释为什么选A Where were you this time yesterday morning?I just stayed home and __TV at thA:wacth B:was wacthing c:had wacthed Where were you this time yesterday morning?I just stayed home and __TV at the moment.A:wacthed B:was wacthing 已知定义域为0到正无穷的函数f(x),同时满足条件：f(2)=1,f（6）=4,f（xy）=f（x）+f（y）,求f（3）和f(9 二项式定理过程我插呀 题目没错啊 是你能力有问题吧？！ 有关二项式定理（1-3a+2b)^5展开式中不含b的项的系数之和是多少?请问为什么可以把b令成0,再把a令成1,然后得到-32, 二项式定理是什么 Where were you when I was burned and broken?Where were you when Iwas hopeless?Because the things you say and the tings you do surround me.I was staright into the shinning sun,lost in throught and lost in time.中文翻译. 英语翻译十万火急! Where were you when I was burned and broken?Where were you when I was hopele (—0.25)+(—3)—负1又4分之3的绝对值—(—3) 化简(二项式定理):(1+√x)^5+(1-√x)^5 如何用二项式定理推算(x+（1/x）-1)^5的展开式? 3（x－1）²－18＝0 二项式定理:(1-根号x)^6*(1+根号x)^4展开式中x的系数是?^指的是平方 若多项式的值与字母x的取值无关求ab的值 已知两个集合A,B是全集U的两个子集合,用维恩图说明集合A交CuB与集合B交CuA的交集是空集最好有图,不画的话把意思说明白也行, 关于二项式定理的.C10取9 + C11取9 + C12取9 + ...+ C19取9 = 结果是C20取10 -1吧还是+1怎么算的?把步骤写下来, 高中必修2数学解析几何复习题2的答案 设全集I={x|1≤x＜9,x属于N},求满足{1,3,5,7,8}与B的补集的集合为{1,3,5,7}的所有集合B的个数 多项式与多项式的差与其中的几个字母因数的取值无关是什么意思? 多项式的乘法与字母取值问题已知计算（x³+mx+n）（x²-5x+3）的结果不含x³和x²项,求m,n的值. Ann and Kate are going to fly kites in the park this afternoon.(改为一般疑问句） 要详细的化简过程和方法,式子如图所见就是图中的根式怎么化简, 把多项式8a^-7a^b+4ab^2+b^3-7,写成两个多项式的和,使其中一个不含字母b的是?另一个是?上次有个提问和我基本一样的 但他那个湿3b的立方 我的是b的立方 主要是第二问,/> 抛物线C的方程为y=ax^2(a不还意思，第二问条件为“向量BM＝入向量MA” where are you going this afternoon?的中文意思是什么 where are you going this afternoon Sarah,where 什么 going to this afternoon