code segmentassume cs:codestart:mov dx,037Bhmov ax,10001011bmov dx,0379hin ax,dxnot axmov dl,alcall DISCHARjmp startretcode endsend startDISCHAR PROCNEAR ;屏幕显示信息MOV AH,2INT 21HRETDISCHAR ENDP

C语言中,code uint8 a[] 里面的code是什么意思? code segmentassume cs:codestart:mov dx,037Bhmov ax,10001011bmov dx,0379hin ax,dxnot axmov dl,alcall DISCHARjmp startretcode endsend startDISCHAR PROCNEAR ;屏幕显示信息MOV AH,2INT 21HRETDISCHAR ENDP 我在学C++BuilderUnable to invoke Code Parameters due to errors in source code 汇编语言mov ax,不太理解中括号在此处的用法可以改写成mov ax,可以解释下这个程序中[ ]的用法吗data segmentbuf db 'ABCDEF'num dw 72,-5,100hpoin dw 0data endscode segmentassume cs:code,ds:datastart:mov ax,datamov ds,axm 汇编97,78,-1,0,32,14,21,27,-20,99 从小到大进行排序 然后逐位加5并输出显示 有知道的吗DATA SEGMENTA DB 97,78,-1,0,32,14,21,27,-20,99B DB 5,5,5,5,5,5,5,5,5,5D DB 10 DUP(?)N EQU 10LEN EQU $-ADATA ENDSCODE SEGMENTASSUME CS:CODE,DS: 问一个很简单滴汇编.unable to open input data segmentT0 EQU 200HT1 EQU 201HT2 EQU 202HCTLT EQU 203Hdata endsCODE SEGMENTASSUME CS:CODE,ds:dataSTART:mov ax,datamov ds,axMOV DX,CTLTMOV AL 00100111OUT DX,ALMOV DX,T0MOV AL,50OUT DX,ALmov dx,CTLTM 统计正负数的个数.下面是我的代码、请高手指点.data segmentdat db 0ffh,54h,8ah,42h,62h,oc6hcount equ $-datt1 db 0;存负数个数t0 db 0；存正数个数data endscode segmentassume cs:code,ds:datastart:mov ax,datamov ds,axxor ax,ax divide overflow急,32位除法源程序：.486DATA SEGMENTNUM1 DD 10000010HNUM2 DW 1000HNUM3 DW NUM4 DW DATA ENDSCODE SEGMENTASSUME CS:CODE,DS:DATASTART:MOV AX,DATAMOV DS,AXLEA SI,NUM1MOV AX,[SI]MOV DX,[SI+2];CWDMOV CX,NUM2;MOV CX,2DIV CXMOV NUM3,DXM 再帮我解几个题吧在正常EOI方式下,中断结束命令是清除( )中的某一位.A.IRR B.ISRC.IMR D.程序状态字分析程序,指出运行结果DATA SEGMENTSUM DB DATA ENDSCODE SEGMENTASSUME CS:CODE,DS:DATASTART:MOV AX,DATAMOV DS,AXXOR A area code / country code friend code CODE是什么意思? zip code NCM code code是什么意思 Confirmaton code SIC Code SIC Code