已知sin(a+P)=1,求证tan(2a+P)+tanP=0
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已知sin(a+P)=1,求证tan(2a+P)+tanP=0
已知sin(a+P)=1,求证tan(2a+P)+tanP=0
已知sin(a+P)=1,求证tan(2a+P)+tanP=0
已知sin(a+P)=1
即a+P=π/2
P= π/2 -a
tan(2a+P)+tanP
=tan( π/2 +a)+tan( π/2 -a)
=-cota+cota
=0
已知sin(a+P)=1,求证tan(2a+P)+tanP=0
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