作业帮已知x²-y²=10,求[（x+y）³-2y(x+y)²-4(x+y)]÷(x+y)的值
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已知x²-y²=10,求[（x+y）³-2y(x+y)²-4(x+y)]÷(x+y)的值
已知x²-y²=10,求[（x+y）³-2y(x+y)²-4(x+y)]÷(x+y)的值
已知x²-y²=10,求[（x+y）³-2y(x+y)²-4(x+y)]÷(x+y)的值
6,后面的多项式,提取（x+y）,变成：
(x+y)[(x+y)^2-2y(x+y)-4]/ (x+y)
=(x+y)^2-2y(x+y)-4
=x^2-y^2-4
=10-4
=6
已知x²-y²=10，
[（x+y）³-2y(x+y)²-4(x+y)]÷(x+y)的值
=（x+y）²-2y(x+y)-4
=(x+y)(x+y-2y)-4
=(x+y)(x-y)-4
=10-4
=6;
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已知x²-y²=10，
[（x+y）³-2y(x+y)²-4(x+y)]÷(x+y)的值
=（x+y）²-2y(x+y)-4
=(x+y)(x+y-2y)-4
=(x+y)(x-y)-4
=10-4
=6;
您好，很高兴为您解答，skyhunter002为您答疑解惑
如果本题有什么不明白可以追问，如果满意记得采纳
如果有其他问题请采纳本题后另发点击向我求助，答题不易，请谅解，谢谢。
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