[(m-3)/(m+5)]^2+[(4-2m)/(m+5)]^2=1,求m
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/01 07:25:43
x)56Ռ3Ҏ05E<ؔkTOZ;jVVlhna Q)*Bx`Y% .kju"g :B.mkcڋV<;h09.Gv-ngk[j\t-ǂ
uˣ- @X↗zx(lgv>_|Vˋ勑 ʕ
[(m-3)/(m+5)]^2+[(4-2m)/(m+5)]^2=1,求m
[(m-3)/(m+5)]^2+[(4-2m)/(m+5)]^2=1,求m
[(m-3)/(m+5)]^2+[(4-2m)/(m+5)]^2=1,求m
[(m-3)/(m+5)]^2+[(4-2m)/(m+5)]^2=1
(m-3)²+ (4-2m)² = (m+5)²
m²-6m + 9 + 16 + 4m² - 16m = m²+10m+25
4m² -32m =0
m²-8m=0
m(m-8) =0
m=0 或者 8
(m-3)²+(4-2m)²=(m+5)²
m²-6m+9+4m²-16m+16=m²+10m+25
4m²-32m=0
∴m=0 m=8
检验:m=0,m=8是方程的解
计算:(m+3m+5m+...+2009m)-(2m+4m+6m+...+2008m)
(m+3m+5m+...+2009m)-(2m+4m+6m+...2008m)
(m+3m+5m+...+2014m)-(2m+4m+6m+...+2013m)
(m+3m+5m+...+2013m)-(2m+4m+6m+...+2012m)
(m+3m+5m+...+2015m)-(2m+4m+6m+...+2014m)=
计算:(m+3m+5m+...+2009m)-(2m+4m+6m+...+2010m)
m-2m-3m+4m-5m-6m+7m.2004m=?
(m+3m+5m.+2013m)-(2m+4m+6m+.+2012m)=?
m-2m-3m+4m-5m-6m+7m-8m-9m+...+2002m-2003m-2004m求m的值
(m+3m+5m+...+2009m)-(2m+4m+...+2008m)怎么算
合并同类项m-2m+3m-4m+5m-.+2011m-2012m
m+3m+5m+...+2011m-2m-4m-...-2010m等于多少?
计算(m+3m+5m+7m+.+2009m)-(2m+4m+6m+.+2008m)
计算(m+3m+5m+7m+.+2013m)-(2m+4m+6m+.+2012m)
(m+3m+5m+7m+.+2009m)-(2m-4m-6m-.-2008m)=?
(m+3m+5m+7m+.+2011m)-(2m+4m+6m+.+2010m) 要说理由!
计算:m-2m-3m+4m-5m-6m+7m-8m-9m+...+2002m-2003m-2004m
m-2m-3m+4m-5m-6m+7m-8m-9m+.+2002m-2003m-2004m