y=e^x^½ 则y'=
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y=e^x^½ 则y'=
y=e^x^½ 则y'=
y=e^x^½ 则y'=
y'=e^x^½ *(x^½)'
=e^x^½ *½x^(½-1)
=½(e^x^½)/x^½
答:
y'=e^x^½*(x^½ )'
=e^x^½*1/2x^(1/2-1)
=1/2(e^x^½)*x^(-1/2)