已知xy=-2,x-y=3,求代数式(-3xy-7y)+[4x-3(xy+y-2x)]的值

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已知xy=-2,x-y=3,求代数式(-3xy-7y)+[4x-3(xy+y-2x)]的值
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已知xy=-2,x-y=3,求代数式(-3xy-7y)+[4x-3(xy+y-2x)]的值
已知xy=-2,x-y=3,求代数式(-3xy-7y)+[4x-3(xy+y-2x)]的值

已知xy=-2,x-y=3,求代数式(-3xy-7y)+[4x-3(xy+y-2x)]的值
(x+y)^2=(x-y)^2+4xy=1
所以x+y=-1或1
解得x=1,y=-2或x=2,y=-1
下来就自己算吧

(-3xy-7y)+[4x-3(xy+y-2x)]
=-3xy-7y+4x-3xy-3y+6x
=-6xy-10y+10x
=-6xy+10(x-y)
=-6*(-2)+10*3
=12+30
=42