(x-1/2y-1)(x-1/2y+1)-(x-1/2y-1)^2,其中x=1.5,y=3.9

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/05 13:47:25
(x-1/2y-1)(x-1/2y+1)-(x-1/2y-1)^2,其中x=1.5,y=3.9
xRN@bqaH D)VE,cH4! BB:X̝+~CAŠݙs<2s\0К8̨3kJ8^ВRK'R޲5n*H(ĩw+S/t^;3=ŃD=b-)cHX I 0;`fe7ǔ~ݒgJXMVBA>)k{Kۯa~/]HjIeELVza[70nq/D2LC[Niǻx U"}:3ȣ>:2

(x-1/2y-1)(x-1/2y+1)-(x-1/2y-1)^2,其中x=1.5,y=3.9
(x-1/2y-1)(x-1/2y+1)-(x-1/2y-1)^2,其中x=1.5,y=3.9

(x-1/2y-1)(x-1/2y+1)-(x-1/2y-1)^2,其中x=1.5,y=3.9
过程写的有点乱,不过应该能看懂
化简(x-1/2y-1)(x-1/2y+1)(x-1/2y-1)^2,第二个我是当+作的
化简
=[(x-1/2y)-1][(x-2y)+1](x-2y-1)^2 注:^这个是乘的意思么?
之后把前两项用平方和还是叫什么名字的合并
变成[(x-1/2y)的2次幂-1][(x-1/2y)-1]^2
然后展开变成
2(x-1/2y)的3次幂-2(x-1/2y)的2次幂-2(x-1/2y)+2

原式=(x-1/2y-1)[(x-1/2y+1)-(x-1/2y-1]
=2(x-1/2y-1)
=2x-y-2
=2*1.5-3.9-2
=-2.9