若数列｛an｝满足a1=1,an+1=2an,n=1,2,3,……,则a1+a2+……+an=____________

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若数列｛an｝满足a1=1,an+1=2an,n=1,2,3,……,则a1+a2+……+an=____________
若数列｛an｝满足a1=1,an+1=2an,n=1,2,3,……,则a1+a2+……+an=____________

若数列｛an｝满足a1=1,an+1=2an,n=1,2,3,……,则a1+a2+……+an=____________
这是个等比数列,公比为2,求和公式:a1*(1-q^n)/(1-q)
化间得2^n-1

你说的是不是 an=2an-1 (n>=2) 如果这样这个是个无穷等比递增级数,公比为2 它不是收敛的数列吧

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