已知︱x+y-2︱+(2xy-1)2=0,求x2+6xy=y2的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/17 12:13:59
![已知︱x+y-2︱+(2xy-1)2=0,求x2+6xy=y2的值](/uploads/image/z/12616440-24-0.jpg?t=%E5%B7%B2%E7%9F%A5%EF%B8%B1x%2By-2%EF%B8%B1%2B%282xy-1%292%3D0%2C%E6%B1%82x2%2B6xy%3Dy2%E7%9A%84%E5%80%BC)
x){}KX]k5**u
5l
tml064z>i"}ِgv
`1. mk *m
hWYF` PNZ36Z@嚶f
qFfsi;v?k0F 1v x
已知︱x+y-2︱+(2xy-1)2=0,求x2+6xy=y2的值
已知︱x+y-2︱+(2xy-1)2=0,求x2+6xy=y2的值
已知︱x+y-2︱+(2xy-1)2=0,求x2+6xy=y2的值
︱x+y-2︱+(2xy-1)2=0 x+y-2=0,x+y=2 2xy-1=0,xy=1/2 x2+6xy+y2=x2+2xy+y2+4xy=(x+y)^2+4xy=2^2+4*(1/2)=6 ^2是平方的意思