1*2*3·········*2005的积的末尾有多少个连续的零

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1*2*3·········*2005的积的末尾有多少个连续的零
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1*2*3·········*2005的积的末尾有多少个连续的零
1*2*3·········*2005的积的末尾有多少个连续的零

1*2*3·········*2005的积的末尾有多少个连续的零
2005÷5取商的整数部分是401
2005÷25取商的整数部分是80
2005÷125取商的整数部分是16
2005÷625取商的整数部分是3
401+80+16+3=500
答:1乘2乘3乘.乘2005的积的末尾有500个连续的0

因数5的个数决定末尾0的个数
2005÷5=401个
2005÷25=80个(取整)
2005÷125=16个(取整)
2002÷625=3(取整)
401+80+16+3=500个
1*2*3*4*5*6*……*2005末尾有500个0

  •  sadac

2005÷5取商的整数部分是401
2005÷25取商的整数部分是80
2005÷125取商的整数部分是16
2005÷625取商的整数部分是3
401+80+16+3=500
所以有500个

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