作业帮设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
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设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
求下导f(x)'=-x^2+4ax-3a^2=-(x-a)(x-3a)
那么x3a函数都是单调递减.
导数大于0说明是单增,反之单减.等于0就是极值
a
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设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0