作业帮设f(x)=(x-1)(x-2)(x-3)(x-4)(x-5),则f’(x)=0在[2,5]内有实根个数为
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设f(x)=(x-1)(x-2)(x-3)(x-4)(x-5),则f’(x)=0在[2,5]内有实根个数为
设f(x)=(x-1)(x-2)(x-3)(x-4)(x-5),则f’(x)=0在[2,5]内有实根个数为
设f(x)=(x-1)(x-2)(x-3)(x-4)(x-5),则f’(x)=0在[2,5]内有实根个数为
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