已知2x-3根号xy-2y=0(x>0),求x^2+4xy-16y^2/x^2+xy-9y^2

已知2x-3根号xy-2y=0(x>0),求x^2+4xy-16y^2/x^2+xy-9y^2
已知2x-3根号xy-2y=0(x>0),求x^2+4xy-16y^2/x^2+xy-9y^2

已知2x-3根号xy-2y=0(x>0),求x^2+4xy-16y^2/x^2+xy-9y^2
2x-3√(xy)-2y=0
(2√x+√y)(√x-2√y)=0
因为x>0,xy≥0
所以y≥0
2√x+√y>0
所以√x-2√y=0,即x=4y
(x^2+4xy-16y^2)/(x^2+xy-9y^2)
=[(4y)^2+4*4y*y-16y^2]/[(4y)^2+4y*y-9y^2]
=16/11

已知2x-3√(xy)-2y=0，则x^2 4xy-16y^2/2x^2 xy-9y^2的值是那个，请问，(2根号x 根号y)(根号x-2根号y)=0是怎么得出来的分解因式学