若f(X)=ax³-bx+5且f(-2)=8,求f(2)

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若f(X)=ax³-bx+5且f(-2)=8,求f(2)
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若f(X)=ax³-bx+5且f(-2)=8,求f(2)
若f(X)=ax³-bx+5且f(-2)=8,求f(2)

若f(X)=ax³-bx+5且f(-2)=8,求f(2)

带入X=-2得:
-8a+2b+5 = 8, 所以,-8a+2b = 3, 故 8a-2b = -3
f(2) = 8a-2b+5 = -3+5 = 2