已知3x-4除以(x-1)(x-4)=a除以x-1+b除以x-2 求整式a b
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/17 04:29:24
![已知3x-4除以(x-1)(x-4)=a除以x-1+b除以x-2 求整式a b](/uploads/image/z/15200941-13-1.jpg?t=%E5%B7%B2%E7%9F%A53x-4%E9%99%A4%E4%BB%A5%EF%BC%88x-1%29%EF%BC%88x-4%EF%BC%89%3Da%E9%99%A4%E4%BB%A5x-1%2Bb%E9%99%A4%E4%BB%A5x-2+%E6%B1%82%E6%95%B4%E5%BC%8Fa+b)
xPMo@+VFzo./B3k6AD@R$pSdSz_`!K^vy$U~~}~~|=}v)Xdۋ3&CET8:{y1}cRW0sHl,fn־8A9ßّ0O#Qt
,Usi zc쳏5~}eK3h^N,Ӿk1hr{ӏU|[ZhT$EYѰ"铮ngE<-6;"6m.
E,\g
10b="
rCD1XrQAedW£&Xgy@{Y/C.s#RacP^1Y k3
已知3x-4除以(x-1)(x-4)=a除以x-1+b除以x-2 求整式a b
已知3x-4除以(x-1)(x-4)=a除以x-1+b除以x-2 求整式a b
已知3x-4除以(x-1)(x-4)=a除以x-1+b除以x-2 求整式a b
题目不对
(3x-4)/[(x-1)(x-2)]=a/(x-1)+b/(x-2)
两边同时乘以(x-1)(x-2)则
3x-4=a(x-2)+b(x-1)=ax-2a+bx-b
所以a+b=3
-2a-b=-4
a=1
将a=1带入式子a+b=3得b=2