{(x+2y)²—(x-2y)²-(x+2y)(x-2y)-4y²}÷2x求x=2014 y=-2014\1

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{(x+2y)²—(x-2y)²-(x+2y)(x-2y)-4y²}÷2x求x=2014 y=-2014\1
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{(x+2y)²—(x-2y)²-(x+2y)(x-2y)-4y²}÷2x求x=2014 y=-2014\1
{(x+2y)²—(x-2y)²-(x+2y)(x-2y)-4y²}÷2x求
x=2014 y=-2014\1

{(x+2y)²—(x-2y)²-(x+2y)(x-2y)-4y²}÷2x求x=2014 y=-2014\1
注意到(x+2y)²—(x-2y)²-(x+2y)(x-2y)=0,所以
原式=-4y²÷2x
=-2y²/x
=-2(-1/2014)²/2014
=-2/2012^3.