求值域y=(1+tanx)/(1-tanx),x∈(-π/2,0)
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求值域y=(1+tanx)/(1-tanx),x∈(-π/2,0)
求值域y=(1+tanx)/(1-tanx),x∈(-π/2,0)
求值域y=(1+tanx)/(1-tanx),x∈(-π/2,0)
x∈(-π/2,0)
tanx0
1-tanx>1
0