若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)=

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若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)=
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若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)=
若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)=

若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)=
(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)
=2x+y-2xy-3x-2y-xy-4xy-3y+5x
=4x-4y-7xy
=4(x-y)-7xy
因为x-y=4,xy=1
所以
原式=4*4-7=16-7=9

x-y=4, xy=1
∴(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)
=2x+y-2xy-3x-2y-xy-4xy-3y+5x
=4x-4y-6xy
=4﹙x-y﹚-6xy
=4× 4-6×1
=10.

=2x+y-2xy-3x-2y-xy-4xy-3y+5x
=4x-4y-7xy
=4(x-y)-7xy
因为x-y=4,xy=1,所以原式=4*4-7*1=9