y-{y-2x+[5x-3(y+2x)+6y]},其中x= - 1/3,y= 1/8.

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y-{y-2x+[5x-3(y+2x)+6y]},其中x= - 1/3,y= 1/8.
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y-{y-2x+[5x-3(y+2x)+6y]},其中x= - 1/3,y= 1/8.
y-{y-2x+[5x-3(y+2x)+6y]},其中x= - 1/3,y= 1/8.

y-{y-2x+[5x-3(y+2x)+6y]},其中x= - 1/3,y= 1/8.
y-{y-2x+[5x-3(y+2x)+6y]}
=y-[y-2x+(5x-3y-6x+6y)]
=y-[y-2x-x+3y]
=y-4y+3x
=3x-3y
=3×(-1/3)-3×1/8
=-11/8

这道题很简单
y-{y-2x+[5x-3(y+2x)+6y]}
=y-[y-2x+(5x-3y-6x+6y)]
=y-[y-2x-x+3y]
=y-4y+3x
=3x-3y
=3×(-1/3)-3×1/8
=-11/8