xy-x-y+1/y²-2y+1
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xy-x-y+1/y²-2y+1
xy-x-y+1/y²-2y+1
xy-x-y+1/y²-2y+1
xy-x-y+1/y²-2y+1
={x(y-1)-(y-1)}/(y-1)²
=(x-1)(y-1)/(y-1)(y-1)
=(x-1)/(y-1)
原式=[x(y-1)-(y-1)]/(y-1)²
=(y-1)(x-1)/(y-1)
=x-1
xy-x-y+1/y²-2y+1=(x-1)/(y-1)