作业帮x[x+y][x+y]-x[x-y]² 分解因式是多少?要步奏讲解.要因式分解
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/08 12:02:52
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x[x+y][x+y]-x[x-y]² 分解因式是多少?要步奏讲解.要因式分解
x[x+y][x+y]-x[x-y]² 分解因式是多少?要步奏讲解.
要因式分解
x[x+y][x+y]-x[x-y]² 分解因式是多少?要步奏讲解.要因式分解
x[x+y][x+y]-x[x-y]²
＝x[(x+y)²－(x-y)²]
=x[(x+y+(x-y)][(x+y)-(x-y)]
=x(2x)(2y)
=4x²y
x[x+y][x+y]-x[x-y]²
=x[(x+y)²-(x-y)²]
=x(x+y+x-y)(x+y-x+y)
=4x²y
x[x+y][x+y]-x[x-y]²
=x[﹙x＋y﹚²－﹙x－y﹚²]
=x[﹙x+y)+(x-y)][﹙x+y)-(x-y)]
=x﹙2x﹚﹙2y﹚
=4x²y
x[(x+y)^2-(x-y)^2]
=x[(x+y+x-y)(x+y-(x-y))]
=x*2x*2y
=4x^2y