函数f(x)满足f(x+2)=x²+3,则f(x)=

函数f(x)满足f(x+2)=x²+3,则f(x)=
函数f(x)满足f(x+2)=x²+3,则f(x)=

函数f(x)满足f(x+2)=x²+3,则f(x)=
f(x+2)=x²+3
=(x+2)²-4x-4+3
=(x+2)²-4(x+2)+7
因此f(x)=x²-4x+7

另x=t-2代入
f(t-2+2)=(t-2)^2+3
即f(t)=(t-2)^2+3=t^2+2t+7
所以f（x）=x^2+2x+7