已知U=R,A=﹛x▏x²+px+12=0﹜,B=﹛x▏x²-5x+q=0﹜若﹙CuA)∩B=﹛2﹜,(CuB)∩A=﹛4﹜,求A∪B
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已知U=R,A=﹛x▏x²+px+12=0﹜,B=﹛x▏x²-5x+q=0﹜若﹙CuA)∩B=﹛2﹜,(CuB)∩A=﹛4﹜,求A∪B
已知U=R,A=﹛x▏x²+px+12=0﹜,B=﹛x▏x²-5x+q=0﹜若﹙CuA)∩B=﹛2﹜,(CuB)∩A=﹛4﹜,求A∪B
已知U=R,A=﹛x▏x²+px+12=0﹜,B=﹛x▏x²-5x+q=0﹜若﹙CuA)∩B=﹛2﹜,(CuB)∩A=﹛4﹜,求A∪B
﹙CuA)∩B=﹛2﹜
所以2∈B
则吧x=2代入x²-5x+q=0
q=6
同理(CuB)∩A=﹛4﹜
则x=4代入A
p=-7
所以解两个方程得到A={3,4},B={2,3}
所以A∪B={3,4,2}