2(x-3/1) +｜y+1｜=0,求6x y-2(x y-2xy-2x )-xy的值2(x-3/1)²+｜y+1｜=0,求6x²y-2(x²y-2xy-2x²)-xy的值

2(x-3/1) +｜y+1｜=0,求6x y-2(x y-2xy-2x )-xy的值2(x-3/1)²+｜y+1｜=0,求6x²y-2(x²y-2xy-2x²)-xy的值
2(x-3/1) +｜y+1｜=0,求6x y-2(x y-2xy-2x )-xy的值
2(x-3/1)²+｜y+1｜=0,求6x²y-2(x²y-2xy-2x²)-xy的值

2(x-3/1) +｜y+1｜=0,求6x y-2(x y-2xy-2x )-xy的值2(x-3/1)²+｜y+1｜=0,求6x²y-2(x²y-2xy-2x²)-xy的值
2（x-3/1）²=0 Iy+1 I=0
（x-3/1)²=0 Y+1=0
x-3/1=0 Y=-1
x=3
6x²y-2(x²y-2xy-2x²)-xy
=6×3²×（-1）-2【3²×（-1）-2×3×（-1）-2×3²】-3×（-1）
=-54-2【-9+6-18】+3
=-54+42+3
=-9
你题是不是错了,应该是1/3而不是3/1,
∴正确的应是：2（x-1/3)²=0 I y+1I =0
(x-1/3）=0 Y+1=0
x=1/3 Y=-1
6x²y-2(x²y-2xy-2x²)-xy
=6×（1/3）²×（-1）-2【（1/3）²×（-1）-2×1/3×（-1）-2×（1/3）²】-1/3×（-1）
=-2/3-2【-1/9+2/3-2/9】+1/3
=-2/3-2×1/3+1/3
=-2/3-2/3+1/3
=-4/3+1/3
=-1

1。哪有3/1这种用法，所以题目错误，至少不规范。
2。有多组解。
3。当y=-1，x=3时，值-9。
4。我觉得原来错误处应该是1/3，那么值该是-1。（虽有多组）

由题意得2(x-3/1)²=0 x=3
｜y+1｜=0 y=-1
所以6x²y-2(x²y-2xy-2x²)-xy=-9