1-(x-1)/3=(x+3)/2 (2y+1)/4-1=y-(10y+1)/12 3x+(x+1)/2=3-(2x-1)/3

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/01 07:01:35
1-(x-1)/3=(x+3)/2 (2y+1)/4-1=y-(10y+1)/12 3x+(x+1)/2=3-(2x-1)/3
xAj@ E &l vA ]t BIHi]lBi)Y|47M"d{8=./G_j|tf,Nj Iw;;}6mOoKu>

1-(x-1)/3=(x+3)/2 (2y+1)/4-1=y-(10y+1)/12 3x+(x+1)/2=3-(2x-1)/3
1-(x-1)/3=(x+3)/2 (2y+1)/4-1=y-(10y+1)/12 3x+(x+1)/2=3-(2x-1)/3

1-(x-1)/3=(x+3)/2 (2y+1)/4-1=y-(10y+1)/12 3x+(x+1)/2=3-(2x-1)/3
1-(x-1)/3=(x+3)/2 两边同时乘以6得
6-2(x-1)=3(x+3)
6-2x+2=3x+9
3x+2x=6+2-9
5x=-1
x=-1/5
(2y+1)/4-1=y-(10y+1)/12 两边同时乘以12得
3(2y+1)-12=12y-(10y+1)
6y+3-12=12y-10y-1
6y-12y+10y=-1-3+12
4y=8
y=2
3x+(x+1)/2=3-(2x-1)/3 两边同时乘以6得
18x+3(x+1)=18-2(2x-1)
18x+3x+3=18-4x+2
18x+3x+4x=18+2-3
25x=17
x=17/25