[(x+3分之x+2)-(x+2分之x+1)+(x+5分之x+4)-(x+4分之x+3)]除以[(x平方+8x+15)分之(x平方+7x+13)]

[(x+3分之x+2)-(x+2分之x+1)+(x+5分之x+4)-(x+4分之x+3)]除以[(x平方+8x+15)分之(x平方+7x+13)]
[(x+3分之x+2)-(x+2分之x+1)+(x+5分之x+4)-(x+4分之x+3)]除以[(x平方+8x+15)分之(x平方+7x+13)]

[(x+3分之x+2)-(x+2分之x+1)+(x+5分之x+4)-(x+4分之x+3)]除以[(x平方+8x+15)分之(x平方+7x+13)]
原式=
[(1-1分之x+5)-(1-1分之x+4))+(1-1分之x+3)-(1-1分之x+2)]*[(x
+3)(x+5)]\(x^2+7x+13)
=[(1分之x+2)-(1分之x+3)+(1分之x+4)-(1分之x+5)]*)]*[(x
+3)(x+5)]\(x^2+7x+13)
=[(3分之(x+2)(x+5))-(1分之(x+3)(x+4))]*[(x
+3)(x+5)]\(x^2+7x+13)
=[3(x+3)]\(x+2)-(x+5\x+4)]\(x^2+7x+13)
=[3(x+3)(x+4)-(x+2)(x+5)]\[(x+2)(x+4)]\(x^2+7x+13)
=[3(x^2+7x+12)-(x^2+7x+100]\[(x+2)(x+4)]\(x^2+7x+13)
=(2x^2+14x+26)\[(x+2)(x+4)]\(x^2+7x+13)
=2\[(x+2）（x+4)]
=(1分之x+2)-(1分之x+4)
请采纳我的答案,谢谢

(x+2)/(x+3)-(x+1)/(x+2)+(x+4)/(x+5)-(x+3)/(x+4)
=[1-1/(x+3)]-[1-1/(x+2)]+[1-1/(x+5)]-[1-1/(x+4)]
=1/(x+2)-1/(x+3)+1/(x+4)-1/(x+5)
=(x+3-x-2)/(x+2)(x+3)+(x+5-x-4)/(x+4)(x+5)
=1/(x^2...

全部展开

(x+2)/(x+3)-(x+1)/(x+2)+(x+4)/(x+5)-(x+3)/(x+4)
=[1-1/(x+3)]-[1-1/(x+2)]+[1-1/(x+5)]-[1-1/(x+4)]
=1/(x+2)-1/(x+3)+1/(x+4)-1/(x+5)
=(x+3-x-2)/(x+2)(x+3)+(x+5-x-4)/(x+4)(x+5)
=1/(x^2+5x+6)+1/(x^2+9x+20)
=(2x^2+14x+26)/(x+2)(x+3)(x+4)(x+5)
=2(x^2+7x+13)/(x+2)(x+3)(x+4)(x+5)
x^2+8x+15=(x+3)(x+5)
所以原式=[2(x^2+7x+13)/(x+2)(x+3)(x+4)(x+5)]*[(x+3)(x+5)/(x^2+7x+13)]
=2/(x+2)(x+4)
=2/(x^2+6x+8)

收起

化简：
原式=[1-1/（x+3）-1+1/(x+2)+1-1/(x+5)-1+1/(x+4)]*(x^2+7x+13)/(x+3)(x+5)
=[1/（x+2）-1/(x+3)+1/(x+4)-1/(x+5)])]*(x^2+7x+13)/(x+3)(x+5)
=[1/(x+2)(x+3)+1/(x+4)(x+5)])]*(x^2+7x+13)/(x+3)(x+5)
=2(x^2+7x+13)/(x+2)(x+3)(x+4)(x+5))*(x^2+7x+13)/(x+3)(x+5)
=2/(x+2)(x+4)

[(x+2)/(x+3)-(x+1)/(x+2)+(x+4)/(x+5)-(x+3)/(x+4)]/[(x^2+7x+13)]/(x^2+8x+15)]
={1-1/(x+3)-[1-1/(x+2)]+1-1/(x+5)-[1-1/(x+4)]}/[(x^2+7x+13)]/(x^2+8x+15)]
=1/(x+2)-1/(x+3)+1/(x+4)-1/(x+5)/[(x^2+7x...

全部展开

[(x+2)/(x+3)-(x+1)/(x+2)+(x+4)/(x+5)-(x+3)/(x+4)]/[(x^2+7x+13)]/(x^2+8x+15)]
={1-1/(x+3)-[1-1/(x+2)]+1-1/(x+5)-[1-1/(x+4)]}/[(x^2+7x+13)]/(x^2+8x+15)]
=1/(x+2)-1/(x+3)+1/(x+4)-1/(x+5)/[(x^2+7x+13)]/(x^2+8x+15)]
=[1/(x+2)(x+3)-1/(x+4)(x+5)]/[(x^2+7x+13)]/(x^2+8x+15)]
=[(4x+14)/(x+2)(x+3)(x+4)(x+5)]/[(x^2+7x+13)]/(x^2+8x+15)]
=[(4x+14)/(x+2)(x+3)(x+4)(x+5)(x^2+8x+15)]/[(x^2+7x+13)]
=[(4x+14)/(x+2)(x+4)]/[(x^2+7x+13)]
=(4x+14)/[(x^2+6x+8)(x^2+7x+13)]

收起

原式=[(1-1分之x+5)-(1-1分之x+4))+(1-1分之x+3)-(1-1分之x+2)]*[(x
+3)(x+5)]\(x^2+7x+13)
=[(1分之x+2)-(1分之x+3)+(1分之x+4)-(1分之x+5)]*)]*[(x
+3)(x+5)]\(x^2+7x+13)
=[(3分之(x+2)(x+5))-(1分之(x+3)(x+4))]*[...

全部展开

原式=[(1-1分之x+5)-(1-1分之x+4))+(1-1分之x+3)-(1-1分之x+2)]*[(x
+3)(x+5)]\(x^2+7x+13)
=[(1分之x+2)-(1分之x+3)+(1分之x+4)-(1分之x+5)]*)]*[(x
+3)(x+5)]\(x^2+7x+13)
=[(3分之(x+2)(x+5))-(1分之(x+3)(x+4))]*[(x
+3)(x+5)]\(x^2+7x+13)
=[3(x+3)]\(x+2)-(x+5\x+4)]\(x^2+7x+13)
=[3(x+3)(x+4)-(x+2)(x+5)]\[(x+2)(x+4)]\(x^2+7x+13)
=[3(x^2+7x+12)-(x^2+7x+100]\[(x+2)(x+4)]\(x^2+7x+13)
=(2x^2+14x+26)\[(x+2)(x+4)]\(x^2+7x+13)
=2\[(x+2）（x+4)]
=(1分之x+2)-(1分之x+4)

收起