sin^a+cos^(π/6+a)+1/2sin(2a+π/6)求值
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/01 07:35:53
x)+̋KN/8ߠomo0Jh>aMR>lH4ٌOvI.#6#\:l5u55A:@ꍵ" !zu`]@y0CQ,c}Z mc(c)+yƩO4 5F 1k O~
sin^a+cos^(π/6+a)+1/2sin(2a+π/6)求值
sin^a+cos^(π/6+a)+1/2sin(2a+π/6)求值
sin^a+cos^(π/6+a)+1/2sin(2a+π/6)求值
是不是sin^2a+cos^2(π/6+a)+1/2sin(2a+π/6)
=(1-cos2a)/2+(1+cos(π/3+2a))/2+1/2sin(2a+π/6)
=1-1/2cos2a+1/4cos2a-√3/4sin2a+√2/4sin2a+1/4cos2a (利用公式展开)
=1
由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证:1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a)
sin^a+cos^(π/6+a)+1/2sin(2a+π/6)求值
sin^2a+cos^2(π/6+a)+1/2sin(2a+π/6)
化简1-sin^4a-cos^4a/1-sin^6a-cos^6a
1-sin^6a-cos^6a分之1-sin^4a-cos^4a 化简
(1-sin^6a-cos^6a)/(1-sin^4a-cos^4a)=?
(1-sin^4a-cos^4a)/(1-sin^6a-cos^6a)
化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)==
[Sin(6π+a)Cos(7π-a)]/[Sin(3π+a)+Sin(-π+a)
(1-sin^6a-cos^6a)/(sin^2a-sin^4a)
化简tan a(cos a-sin a)+sin a(sin a+tan a)/1+cos a
化简:(sin^6a+cos^6a-1) / (sin^4ª+cos^4a-1)
求证1+sin a+cos a+2sin acos a/1+sin a+cos a=sin a+cos a
Sina+sin^2a=1,cos^2a+cos^s4a+cos^6a
已知sin[a-b]cos a-cos[b-a]sin a=3/5,b是第三象限角,求sin[b+5π/4]的值第一题1/2cos x-√3/2sin x第二题√3sin x+cos x第三题√2[sin x-cos x]第四题√2cos x-√6sin x
求证:sin 2a/1+sin a+cos a=sin a+cos a-1急
当sinˆa+sin^2a=1求cos^+cos^6的值
=1-(sin^6a+cos^6a) ------(1)=1-(sin^a+cos^a)(sin^4 a-sin^acos6a+cos^4 a) --------(2)由(1)怎么能到(2)呢=1-(sin^6a+cos^6a)=1-(sin^2a+cos^2a)(sin^4 a-sin^2acos^2a+cos^4a)