若△ABC中,2√2(sin^2A-sin^2C)=(a-b)sinB外接圆半径为√21求角C2求面积最大值

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/28 07:53:23
若△ABC中,2√2(sin^2A-sin^2C)=(a-b)sinB外接圆半径为√21求角C2求面积最大值
xRJ1mBSz,.lEDHKO"H/SdBS^{73i,/KbX\݃v(N^DHd4H4NwOk-{<^2$Y j4F'D8iF67"@=ǡd ֬Jۊ}d 7[eQ-Gf'rHî6*A!3^gOTM#L˳s^PRloƂ.B*- b@^l 歼/7߀ n'j7o|

若△ABC中,2√2(sin^2A-sin^2C)=(a-b)sinB外接圆半径为√21求角C2求面积最大值
若△ABC中,2√2(sin^2A-sin^2C)=(a-b)sinB外接圆半径为√2
1求角C
2求面积最大值

若△ABC中,2√2(sin^2A-sin^2C)=(a-b)sinB外接圆半径为√21求角C2求面积最大值
√2=a/(2sinA)=b/(2sinB)=c/(2sinC)
sinA=a/(2√2)
sinB=b/(2√2)
sinC=c/(2√2)
sin^2A-sin^2C=(a^2-c^2)/8
2√2(sin^2A-sin^2C)=(a-b)sinB
2√2(a^2-c^2)/8=(a-b)b/(2√2)
a^2-c^2=(a-b)b=ab-b^2
c^2=a^2+b^2-ab*1
=a^2+b^2-2ab*cosC
∴2cosC=1
cosC=1/2
∠C=π/3
c=2√2sinC=√6
面积S=c^2sinAsinB/[2sin(A+B)]
=c^2sinAsinB/(2sinC)
=6sinAsinB/√3
=2√3[cos(A-B)-cos(A+B)]
=2√3[cos(A-B)+cosC]
=2√3[cos(A-B)+1/2]
A=B时,cos(A-B)=1,S最大=3√3