已知函数f(x)=cos(x+π/4)cos(x-π/4)+2tsinxcosx-sin(x+π/4)cos(x-π/4)1.当t=2时,求f(x)在[0,π/2]上的最大值和最小值2.若函数f(x)在区间(π/12,π/6)上时增函数,求实数t的取值范围

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 03:06:07
已知函数f(x)=cos(x+π/4)cos(x-π/4)+2tsinxcosx-sin(x+π/4)cos(x-π/4)1.当t=2时,求f(x)在[0,π/2]上的最大值和最小值2.若函数f(x)在区间(π/12,π/6)上时增函数,求实数t的取值范围
xQJP4Is(Ă&.2`@AB-DѕT)ZJ Cu/8s0+ݹw9g\x}^\4*Bu"\W%%|?BGKe;,ҧ҂fU5,Gi/{&p3cyZ1$H$FH`CET~I#౏./QhiK%MW \GHA! #L be۠㵚F#;':8D2|4&riLq+ʎnזVOLoZ*NEnpL/JK`?e

已知函数f(x)=cos(x+π/4)cos(x-π/4)+2tsinxcosx-sin(x+π/4)cos(x-π/4)1.当t=2时,求f(x)在[0,π/2]上的最大值和最小值2.若函数f(x)在区间(π/12,π/6)上时增函数,求实数t的取值范围
已知函数f(x)=cos(x+π/4)cos(x-π/4)+2tsinxcosx-sin(x+π/4)cos(x-π/4)
1.当t=2时,求f(x)在[0,π/2]上的最大值和最小值
2.若函数f(x)在区间(π/12,π/6)上时增函数,求实数t的取值范围

已知函数f(x)=cos(x+π/4)cos(x-π/4)+2tsinxcosx-sin(x+π/4)cos(x-π/4)1.当t=2时,求f(x)在[0,π/2]上的最大值和最小值2.若函数f(x)在区间(π/12,π/6)上时增函数,求实数t的取值范围
f(x)=cos(x+π/4+x-π/4)+tsin2x=cos2x+tsin2x
1.t=2时,f(x)=cos2x+2sin2x=√5sin(2x+arctan0.5)
在x∈[0,π/2]上,f(x)最大值为√5
f(x)最小值为√5sin(2*π/2+arctan0.5)=-1
2.f(x)=√(t^2+1)sin(2x+arctan(1/t))
f(x)在x∈[π/12,π/6]上为增函数
-π/2