要用方程1 there is a double-digit number.The figure on its single is 1 larger than that on its tenth-digit ,and the double digit numbei is 5 times as large as the sum of figures on its tenth-digit and on its single-digit.Question:what is the doub

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要用方程1 there is a double-digit number.The figure on its single is 1 larger than that on its tenth-digit ,and the double digit numbei is 5 times as large as the sum of figures on its tenth-digit and on its single-digit.Question:what is the doub
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要用方程1 there is a double-digit number.The figure on its single is 1 larger than that on its tenth-digit ,and the double digit numbei is 5 times as large as the sum of figures on its tenth-digit and on its single-digit.Question:what is the doub
要用方程
1 there is a double-digit number.The figure on its single is 1 larger than that on its tenth-digit ,and the double digit numbei is 5 times as large as the sum of figures on its tenth-digit and on its single-digit.Question:what is the double-digit number?2 there is a double-digit number.The figure on its tenth-digit is 1 smaller than that on its single digit.If the figures on its tenth-digit and on its single-digit are exchand,the newly-got number will be 9 larger than the original one.Question::what is the original double-digit?

要用方程1 there is a double-digit number.The figure on its single is 1 larger than that on its tenth-digit ,and the double digit numbei is 5 times as large as the sum of figures on its tenth-digit and on its single-digit.Question:what is the doub
用一元.
两个数你设为x和x+1
(x+x+1)*5=10x+x+1
10x+5=11x+1
x=4
x+1=5
最后就是45了

其实这个不难
两位数嘛~然后求这个两位数就好
假设个位数是x,十位数是y,这个数就是10y+x
根据第一句话:个位数比十位数大1,也就是x-y=1
根据第二句话:(个位数+十位数)的五倍就是原数,也就是(x+y)*5=10y+x
其实根据这两个式子简化就是:
x-y=1
x-y=1/5 x
也就是1=1/5 x
即x=5,y=...

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其实这个不难
两位数嘛~然后求这个两位数就好
假设个位数是x,十位数是y,这个数就是10y+x
根据第一句话:个位数比十位数大1,也就是x-y=1
根据第二句话:(个位数+十位数)的五倍就是原数,也就是(x+y)*5=10y+x
其实根据这两个式子简化就是:
x-y=1
x-y=1/5 x
也就是1=1/5 x
即x=5,y=4
数目就是45
至于后面的限制条件根本就不用看了
什么十位数比个位数小1
什么十位数个位数互换比原来的数目大9
毕竟就是两个未知数,X,Y
所以只要两个方程就好了~~

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1.两位数嘛~然后求这个两位数就好
假设个位数是x,十位数是y,这个数就是10y+x
根据第一句话:个位数比十位数大1,也就是x-y=1
根据第二句话:(个位数+十位数)的五倍就是原数,也就是(x+y)*5=10y+x
其实根据这两个式子简化就是:
x-y=1
x-y=1/5 x
也就是1=1/5 x
即x=5,y=4
数目就...

全部展开

1.两位数嘛~然后求这个两位数就好
假设个位数是x,十位数是y,这个数就是10y+x
根据第一句话:个位数比十位数大1,也就是x-y=1
根据第二句话:(个位数+十位数)的五倍就是原数,也就是(x+y)*5=10y+x
其实根据这两个式子简化就是:
x-y=1
x-y=1/5 x
也就是1=1/5 x
即x=5,y=4
数目就是45
至于后面的限制条件根本就不用看了
什么十位数比个位数小1
什么十位数个位数互换比原来的数目大9
毕竟就是两个未知数,X,Y 2.用一元......
两个数你设为x和x+1
(x+x+1)*5=10x+x+1
10x+5=11x+1
x=4
x+1=5
最后就是45了

收起