计算：[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]

来源：学生作业帮助网 编辑：作业帮 时间：2024/05/14 09:04:30
计算：[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]
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计算：[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]
计算：[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]

计算：[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]
[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]
=(x-1)²/[(x-2)(x+1)]²/(x-1)²/(2-x)/{1/[x²(x+1)²]}
=(x-1)²/[(x-2)(x+1)]²/(x-1)²/(2-x)*x²*(x+1)²
=-x²/(x-2)

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