如图,在△ABC中,AB=AC,BE⊥AC,CF⊥AB,垂足分别为点E、F,BE、CF相交于点H,求证:直线AH为△ABC的对称轴急啊,作业啊,在5分钟之内有过程的追加
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![如图,在△ABC中,AB=AC,BE⊥AC,CF⊥AB,垂足分别为点E、F,BE、CF相交于点H,求证:直线AH为△ABC的对称轴急啊,作业啊,在5分钟之内有过程的追加](/uploads/image/z/7572171-3-1.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2CAB%3DAC%2CBE%E2%8A%A5AC%2CCF%E2%8A%A5AB%2C%E5%9E%82%E8%B6%B3%E5%88%86%E5%88%AB%E4%B8%BA%E7%82%B9E%E3%80%81F%2CBE%E3%80%81CF%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9H%2C%E6%B1%82%E8%AF%81%3A%E7%9B%B4%E7%BA%BFAH%E4%B8%BA%E2%96%B3ABC%E7%9A%84%E5%AF%B9%E7%A7%B0%E8%BD%B4%E6%80%A5%E5%95%8A%2C%E4%BD%9C%E4%B8%9A%E5%95%8A%2C%E5%9C%A85%E5%88%86%E9%92%9F%E4%B9%8B%E5%86%85%E6%9C%89%E8%BF%87%E7%A8%8B%E7%9A%84%E8%BF%BD%E5%8A%A0)
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