若一元二次方程x²-2x-3599=0的两根为a.b且a>b求2a-b等于几
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/17 23:40:14
![若一元二次方程x²-2x-3599=0的两根为a.b且a>b求2a-b等于几](/uploads/image/z/93339-27-9.jpg?t=%E8%8B%A5%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8Bx%26%23178%3B-2x-3599%3D0%E7%9A%84%E4%B8%A4%E6%A0%B9%E4%B8%BAa.b%E4%B8%94a%3Eb%E6%B1%822a-b%E7%AD%89%E4%BA%8E%E5%87%A0)
xN@_ĨuCS,]
zimK].蛘9PW%UjbRws3#ʰե^;4Utǽ1?WkkH0P*Iwvw9>uEޱh-H-#kLuEÉ1IE,ꂁbF^\(02AU)'5z*
M]]W
Z9+rHhuv~q64zLKByLBk9
若一元二次方程x²-2x-3599=0的两根为a.b且a>b求2a-b等于几
若一元二次方程x²-2x-3599=0的两根为a.b且a>b求2a-b等于几
若一元二次方程x²-2x-3599=0的两根为a.b且a>b求2a-b等于几
x²-2x-3599=0
x²-2x+1=3600
(x-1)²=3600
x-1=±60
x1=61, x2=-59
∴a=61, b=-59
2a-b
=61×2+59
=181
方程变形:
x²-2x+1=3600
完全平方式
(x-1)²=3600
就知道a,b值了
x²-2x+1-1-3599=0
x²-2x+1=3600
(x-1)²=3600 两根为61和-59,
则2a-b=2*61+59=181
因式分解x²-2x-3599=0即:(x-61)(x+59)=0
x²-2x+1-1-3599=0
x²-2x+1=3600
(x-1)²=3600 两根为a=61和b=-59,
则2a-b=2*61-(-59)=181