f(X)=sin2x+acos2x,且π/4是函数y=f(x)的零点.1.求a的值,并求函数f(x)的最小正周期.2.若∈【0,π】,求函数f(x)的值域,并写出f(x)取得最大值时x的值上面题目我打错了 acos2x 应该是 acos^2 x
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![f(X)=sin2x+acos2x,且π/4是函数y=f(x)的零点.1.求a的值,并求函数f(x)的最小正周期.2.若∈【0,π】,求函数f(x)的值域,并写出f(x)取得最大值时x的值上面题目我打错了 acos2x 应该是 acos^2 x](/uploads/image/z/1043079-15-9.jpg?t=f%28X%29%3Dsin2x%2Bacos2x%2C%E4%B8%94%CF%80%2F4%E6%98%AF%E5%87%BD%E6%95%B0y%3Df%EF%BC%88x%EF%BC%89%E7%9A%84%E9%9B%B6%E7%82%B9.1.%E6%B1%82a%E7%9A%84%E5%80%BC%2C%E5%B9%B6%E6%B1%82%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F.2.%E8%8B%A5%E2%88%88%E3%80%900%2C%CF%80%E3%80%91%2C%E6%B1%82%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%E7%9A%84%E5%80%BC%E5%9F%9F%2C%E5%B9%B6%E5%86%99%E5%87%BAf%EF%BC%88x%EF%BC%89%E5%8F%96%E5%BE%97%E6%9C%80%E5%A4%A7%E5%80%BC%E6%97%B6x%E7%9A%84%E5%80%BC%E4%B8%8A%E9%9D%A2%E9%A2%98%E7%9B%AE%E6%88%91%E6%89%93%E9%94%99%E4%BA%86+acos2x+%E5%BA%94%E8%AF%A5%E6%98%AF+acos%5E2+x)
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