Find the centroid of the region bounded by the given curves.1.y=4x,x=7,x-axis 2.x+8y=8,y-axis,x-axis3.y=7x,y=28,y-axis4.y=x^2-16x,x-axis5.16x-x^3,x-axis,第一象限6.y=26x-x^2,y=x

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/15 06:46:15
Find the centroid of the region bounded by the given curves.1.y=4x,x=7,x-axis 2.x+8y=8,y-axis,x-axis3.y=7x,y=28,y-axis4.y=x^2-16x,x-axis5.16x-x^3,x-axis,第一象限6.y=26x-x^2,y=x
xSn@~=6clJ6%'Jj-(-D AҖh@軴 Lv(jrdK;7?jA\zjAܮ-qT9Qv=Uvi#SF SK@8lڊm eOqB@XŤO& gMi+p=~wi YX\I8O0Ë[|o÷v=nx#Kz|&aJ@1D[ t>5Tي~>bI0de֪khl? fXbѐh%Duh^׆5#SLR54D͕ Lqq߮'PsZD%FRaO8[OEヌ:8#LqrV"!KX|7F_ol~|r 3(( %E+2XskxU2A+52@VNkJ^^>7]*8x_< w۝(g(

Find the centroid of the region bounded by the given curves.1.y=4x,x=7,x-axis 2.x+8y=8,y-axis,x-axis3.y=7x,y=28,y-axis4.y=x^2-16x,x-axis5.16x-x^3,x-axis,第一象限6.y=26x-x^2,y=x
Find the centroid of the region bounded by the given curves.
1.y=4x,x=7,x-axis
2.x+8y=8,y-axis,x-axis
3.y=7x,y=28,y-axis
4.y=x^2-16x,x-axis
5.16x-x^3,x-axis,第一象限
6.y=26x-x^2,y=x

Find the centroid of the region bounded by the given curves.1.y=4x,x=7,x-axis 2.x+8y=8,y-axis,x-axis3.y=7x,y=28,y-axis4.y=x^2-16x,x-axis5.16x-x^3,x-axis,第一象限6.y=26x-x^2,y=x
1.y=4x,x=7,x-axis
∫4xdx|[0,7]=2x^2|[0,7]=98
2、x+8y=8,y-axis,x-axis
y=1-x/8,0≤x≤8
∫(1-x/8)dx|[0,8]=x-1/16*x^2|[0,8]=4
3、 y=7x,y=28,y-axis
x=y/7
∫y/7dy|[0,28]=y^2/14|[0,28]=56
4、y=x^2-16x,x-axis
x^2-16x=0,x=0或16
∫(x^2-16x)dx|[16,0]=1/3*x^3-8x^2|[16,0]=2048/3
5、16x-x^3,x-axis,第一象限
16x-x^3>0,x(x-4)(x+4)<0
x>0,所以积分范围为0<x<4
∫(16x-x^3)dx|[0,4]=8x^2-1/4*x^4|[0,4]=64
6、y=26x-x^2,y=x
代入得
x=26x-x^2,解得x1=25,x2=0,所以积分范围为[0,25]
∫(26x-x^2-x)dx|[0,25]=25/2*x^2-1/3x^3=15625/6

Find the area of the region bounded by the curves and the x-axis 真是复杂啊。~~~ 还是数学题。。。我可没学过!我才初中 对不