题有点多,无聊的帮下忙了!

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题有点多,无聊的帮下忙了!
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题有点多,无聊的帮下忙了!
题有点多,无聊的帮下忙了!

题有点多,无聊的帮下忙了!
13.求由方程x/z=ln(z/y)所确定的函数z=f(x,y)的全微分.
作函数F(x,y,z)=x/z-ln(z/y)=0
则∂z/∂x=-(∂F/∂x)/(∂F/∂z)=-(1/z)/[-(x/z²)-(1/y)/(z/y)]=z/(x+z)
∂z/∂y=-(∂F/∂y)/(∂F/∂z)=-[(-z/y²)/(z/y)]/[-(x/z²)-(1/y)/(z/y)]
=-z²/[y(x+z)]
故dz=[z/(x+z)]dx-[z²/y(x+z)]dy
19.求由方程x+2y+z-2√(xyz)=0所确定的函数z=f(x,y)的全微分.
设F(x,y,z)=x+2y+z-2√(xyz)=0,则:
∂z/∂x=-(∂F/∂x)/(∂F/∂z)=-[1-(yz/√xyz)]/[1-(xy/√xyz)]
=-[√(xyz)-yz]/[√(xyz)-xy]
∂z/∂y=-(∂F/∂y)/(∂F/∂z)=-[2-(xz/√xyz)]/[[1-(xy/√xyz)]
=-[2√(xyz)-xz]/[√(xyz)-xy]
故dz={-[√(xyz)-yz]dx-[2√(xyz)-xz]dy}/[√(xyz)-xy]
20.求微分方程y'+x/y=0满足初始条件y(0)=4的特解
dy/dx=-x/y,分离变量得ydy=-xdx,
积分之得通解为 y²/2=-x²/2+C;
代入初始条件y(0)=4得C=8,故得特解为 y²=-x²+16

多少分,我全做。