25度,Ag2CrO4 ksp……,25度,Ag2CrO4 ksp=2.0*10^-12 ,CH3COOH ,ka=1.8*10^-5,HNO2,Ka=4.6*10^-4,H2SO3Ka1=1.5*10^-2,ka2=1.0*10^-7B.向0.1mol/lCH3COOH溶液中滴加NaOH至c(CH3COOH):c(CH3COO-)=5:9,此时pH=5C.亚硫酸钠溶液中滴加少量HNO2溶液
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![25度,Ag2CrO4 ksp……,25度,Ag2CrO4 ksp=2.0*10^-12 ,CH3COOH ,ka=1.8*10^-5,HNO2,Ka=4.6*10^-4,H2SO3Ka1=1.5*10^-2,ka2=1.0*10^-7B.向0.1mol/lCH3COOH溶液中滴加NaOH至c(CH3COOH):c(CH3COO-)=5:9,此时pH=5C.亚硫酸钠溶液中滴加少量HNO2溶液](/uploads/image/z/11132773-61-3.jpg?t=25%E5%BA%A6%2CAg2CrO4+ksp%E2%80%A6%E2%80%A6%2C25%E5%BA%A6%2CAg2CrO4+ksp%3D2.0%2A10%5E-12+%2CCH3COOH+%2Cka%3D1.8%2A10%5E-5%2CHNO2%2CKa%3D4.6%2A10%5E-4%2CH2SO3Ka1%3D1.5%2A10%5E-2%2Cka2%3D1.0%2A10%5E-7B.%E5%90%910.1mol%2FlCH3COOH%E6%BA%B6%E6%B6%B2%E4%B8%AD%E6%BB%B4%E5%8A%A0NaOH%E8%87%B3c%28CH3COOH%29%3Ac%28CH3COO-%29%3D5%3A9%2C%E6%AD%A4%E6%97%B6pH%3D5C.%E4%BA%9A%E7%A1%AB%E9%85%B8%E9%92%A0%E6%BA%B6%E6%B6%B2%E4%B8%AD%E6%BB%B4%E5%8A%A0%E5%B0%91%E9%87%8FHNO2%E6%BA%B6%E6%B6%B2)
25度,Ag2CrO4 ksp……,25度,Ag2CrO4 ksp=2.0*10^-12 ,CH3COOH ,ka=1.8*10^-5,HNO2,Ka=4.6*10^-4,H2SO3Ka1=1.5*10^-2,ka2=1.0*10^-7B.向0.1mol/lCH3COOH溶液中滴加NaOH至c(CH3COOH):c(CH3COO-)=5:9,此时pH=5C.亚硫酸钠溶液中滴加少量HNO2溶液
25度,Ag2CrO4 ksp……,
25度,Ag2CrO4 ksp=2.0*10^-12 ,CH3COOH ,ka=1.8*10^-5,HNO2,Ka=4.6*10^-4,H2SO3Ka1=1.5*10^-2,ka2=1.0*10^-7
B.向0.1mol/lCH3COOH溶液中滴加NaOH至c(CH3COOH):c(CH3COO-)=5:9,此时pH=5
C.亚硫酸钠溶液中滴加少量HNO2溶液的离子方程式为SO32-+HNO2=HSO3-+NO2-
B对C错,
25度,Ag2CrO4 ksp……,25度,Ag2CrO4 ksp=2.0*10^-12 ,CH3COOH ,ka=1.8*10^-5,HNO2,Ka=4.6*10^-4,H2SO3Ka1=1.5*10^-2,ka2=1.0*10^-7B.向0.1mol/lCH3COOH溶液中滴加NaOH至c(CH3COOH):c(CH3COO-)=5:9,此时pH=5C.亚硫酸钠溶液中滴加少量HNO2溶液
B很容易算啊,pH=pKa-lg(5/9)=5(这个由缓冲溶液的pH计算公式直接带入就行,当然如果你不知道这个公式就去查大学任何一本无机化学或分析化学教材吧)
C更明显了,由于HNO2的Ka