求∫(x^3+66)/x^2+7x+12)dx

来源：学生作业帮助网编辑：作业帮时间：2024/06/17 13:26:31

x��N�0�_U%2�۱c�Y�- _;!� ��u@L��Ca�MP�9H�"!!T��>��\}>Nʵϧ��G��fH��wu�xn?)w쁩*�)��`�ѝ��N>�+�ݼ(��_u��k��,/��|�mB�zL��ݞVVP J2`$��E6K9��D��#�SE�؅Ds��D*�ZȄ��8$�[ݽ�AI��£ ��fa��4�� <�$�R(�O�&.\�%�S��d��s��쎮9~�e��ǣ��.��L>�j��f��t�xt�gO��(z�F�H��

求∫(x^3+66)/x^2+7x+12)dx
求∫(x^3+66)/x^2+7x+12)dx

求∫(x^3+66)/x^2+7x+12)dx
(x³+66)÷(x²+7x+12)=x-7余37x+150
所以(x³+66)÷(x²+7x+12)=x-7+(37x+150)/(x+3)(x+4)
令(37x+150)/(x+3)(x+4)
=a/(x+3)+b/(x+4)
=(ax+bx+4a+3b)/(x+3)(x+4)
所以a=39,b=-2
所以原式=∫[x-7+39/(x+3)-2/(x+4)]dx
=x²/2-7x+39ln|x+3|-2ln|x+4|+C

求∫(x^3+66)/x^2+7x+12)dx 求一个数独答案X X X 9 X X X 8 2 X 6 3 X X 1 4 X 99 X 8 X X X X X XX X X 6 7 X 3 X XX 4 6 X 5 X 2 9 XX X 7 X 2 3 X X XX X X X X X 7 X 17 X 4 3 X X 6 2 X6 3 X X X 7 X X X 求x^3-7x^2+12x因式分解,快~ 求∫(x^3+66)/(x^2+7x+12)dx(x³+66)÷(x²+7x+12)=x-7余37x+150这是怎样得出的呢? 若多项式2x*x*x*x-3x*x*x+ax*x+7x+b能被x*x+x-2整除,求a:b 用递归法求y=x-(x*x*x/3!)+(x*x*x*x*x/5!)-(x*x*x*x*x*x*x/7!)+. 如果3x^3-x=1,求9x^4+12x^3-3x^2-7x+1 *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || (x-1)(x-2)(x-3)(x-4)=(x+5)(x+6)(x+7)求X等于几? 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x 已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^+x^6+x^7+x^8的值如果1+x+x^2+x^3=0,求x+x^2+X^3+x^4+x^5+x^6+x^7+x^8的值, 已知x=2π+1求 |x-1|+|x-2|+|x-3|+|x-4|+|x-5|+|x-6|+|x-7|+|x-8|+|x-9|+|x-10| 已知x=2π+1.求(X-1)+(X-2)+(X-3)+(X-4)+(X-5)+(X-6)+(X-7)+(X-8)+(X-9)+(X-10) 求|x-3|+|x-5|+|x-2|+|x+1|+|x+7|的最小值求|x-3|+|x-5|+|x-2|+|x+1|+|x+7|的最小值已知4x^2+7x-1=3,求-12x^2-21x 已知a(x*x+x-c)+b(2x*x-x-2)=7x*x+4x+3x.求a,b,c的值 1X?+2X?+3X?+4X?+5X?+6X?+7X?+8X?+9X?+10X?=1980求?是多少