{(x+y)分之2-(x-y)分之1=7 {(x+y)分之1+(x-y)分之1=-1

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{(x+y)分之2-(x-y)分之1=7 {(x+y)分之1+(x-y)分之1=-1
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{(x+y)分之2-(x-y)分之1=7 {(x+y)分之1+(x-y)分之1=-1
{(x+y)分之2-(x-y)分之1=7 {(x+y)分之1+(x-y)分之1=-1

{(x+y)分之2-(x-y)分之1=7 {(x+y)分之1+(x-y)分之1=-1
设1/(x+y)=a 1/(x-y)=b
∴原方程组可化为
2a-b=7
a+b=-1
解这个方程组得
a=2
b=-3
∴1/(x+y)=2
1/(x-y)=-3
∴x+y=1/2
x-y=-1/3
∴x=1/12
y=5/12