#define S(x)4 *(x)*x+1 main() {int k=5,j=2;printf("%d\n",S(k+j));}

#define s(x) 3 #define S(x) 3 #define S(x) 4*(x)*x+1 s(4)怎么计算 define fun(x, #define configASSERT( x ) #define min(x,y) (x #define MIN(x,y)(x) #define __T(x) L ## x #define get2byte(x) ((x)[0] 若有宏定义# define s(x) x*x-x,设int k=3; 问cout )define f(x)(x*x) 和 define f(x) x*x 之间的差别. #define N 10#define s(x) x*x#define f(x) (x*x)main(){int i1,i2;i1=1000/s(N);i2=1000/f(N);printf(%d %d ,i1,i2);}运行结果是? #define SETBIT(x,y) (x|=(1 #define MEM_B( x ) ( *( (byte *) (x) ) 我看不懂 #define get_u8(X,O) (*(u8 *)(((u8 *)X) + #define S(x) 4*x*x+1 main() { int i=6,j=8; printf(%d ,S(i+j)); } #define S(x) 4*x*x+1 main() { int i=6,j=8; printf(%d ,S(i+j)); } #define S(x)4 *(x)*x+1 main() {int k=5,j=2;printf(%d ,S(k+j));}