设lim（(x^2+1)/(x+1) -ax-b）=0,求a,b.x趋向无穷大

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设lim（(x^2+1)/(x+1) -ax-b）=0,求a,b.x趋向无穷大
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设lim（(x^2+1)/(x+1) -ax-b）=0,求a,b.x趋向无穷大
设lim（(x^2+1)/(x+1) -ax-b）=0,求a,b.x趋向无穷大

设lim（(x^2+1)/(x+1) -ax-b）=0,求a,b.x趋向无穷大
lim[(x^2+1)/(x+1) -ax-b]
=lim[(x+1)-2x/(x+1)-ax-b]
=lim[(1-a)x-(1+b)]
=0
1-a=0 a=1
1+b=0 b=-1

用Mathematic输入limt[(x^2+1)/(x+1) -ax-b）,x->infinity]
得1-a,因1-a=0，所以a=1
输入limt[(x^2+1)/(x+1) -x-b）,x->infinity]
得-1-b,因-1-b=0，所以b=-1

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