Y=cos2X-2√3sinxcosx化简

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Y=cos2X-2√3sinxcosx化简
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Y=cos2X-2√3sinxcosx化简
Y=cos2X-2√3sinxcosx化简

Y=cos2X-2√3sinxcosx化简
y=cos2x-2√3sinxcosx
=cos2x-√3(2sinxcosx)
=cos2x-√3sin2x
=2(1/2*cos2x-√3/2*sin2x)
=cos2xcosπ/3-sin2xsinπ/3
=cos(2x+π/3)

Y=cos2X-2√3sinxcosx化简 化简：y=cos2x+2sinxcosx-sin2x 已知函数y=sin2x+2sinxcosx-3cos2x,x∈Rsin2x cos2x都是平方 函数y=sinxcosx+√3cos2x-√3/2的最小周期是? y=3sinxcosx+（√3/2）cos2x的值域 y=cos2x-2√3sinxcosx的最小正周期 函数y=√3sinxcosx-1/2cos2x的最小正周期, y=cos2x-2√3sinxcosx相邻两对称轴距离 求函数y=√3sinxcosx-1/2cos2x的值域 1+cos2x+√3/2*(sinxcosx)化简具体步骤 f(x)=sinxcosx+√3/2cos2x怎么化简 化简函数f（x）=√3sinxcosx-cos2x-1/2 请帮我化简 y=Cos2x+SinxCosx y= 4cos2x+4 sinxcosx-2= y= 4cos2x+4 sinxcosx－2 化简 求函数y=sinxcosx+2cos2x的最大值、最小值 y=cos2x+sinxcosx的值域y=cos^2X+sinXcosX 求函数y=√3cos2x+sinxcosx的最大值、最小值、周期