设集合M={y|y=|cos^2-sin^2|,x属于R},N={x||x-(1/i)|

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设集合M={y|y=|cos^2-sin^2|,x属于R},N={x||x-(1/i)|
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设集合M={y|y=|cos^2-sin^2|,x属于R},N={x||x-(1/i)|
设集合M={y|y=|cos^2-sin^2|,x属于R},N={x||x-(1/i)|<根号2,i为虚数单位,x属于R},则M交N为 A.(0.
设集合M={y|y=|cos^2-sin^2|,x属于R},N={x||x-(1/i)|<根号2,i为虚数单位,x属于R},则M交N为
A.(0.1)B.(0.1]C.[0.1)D.[0.1]

设集合M={y|y=|cos^2-sin^2|,x属于R},N={x||x-(1/i)|
y=|cos^2 x-(1-cos^2 x)|=|2cos^2 x-1|,
-1