如图:AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC……如图,AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC.

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如图:AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC……如图,AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC.
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如图:AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC……如图,AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC.
如图:AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC……
如图,AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC.

如图:AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC……如图,AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC.
易证两个大三角形全等,所以,∠C=∠B,∠EAC=∠DAB,因为∠DOC是公共角,所以∠EAD=∠CAB.因为∠CFO和∠BFA是对顶角,所以相等,又∠C=∠B,所以∠BOC=∠CAB,所以:∠CAB=∠EAD=∠BOC.