数列[An]满足An+1-An+3=0,且A1=-5.求An.

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/24 00:58:57
数列[An]满足An+1-An+3=0,且A1=-5.求An.
x){6uӎюyv/|mc.05yc޳Myz6IE$/!ÆK^.l';zP&TY-zO[;bg ?ӞiOv(u5~dR<~I/M{p'H5OufB@8:jhM55ttn(v̫|0 b&X<;~

数列[An]满足An+1-An+3=0,且A1=-5.求An.
数列[An]满足An+1-An+3=0,且A1=-5.求An.

数列[An]满足An+1-An+3=0,且A1=-5.求An.
此题是不是A(n+1)-An+3=0的.先当这样,此式可化为A(n+1)=An-3所以此数列是首项为A1,公差为-3的数列,所以An=A1+d(n-1)=-5-3(n-1)=-3n-2,即数列{An}的通项为-3n-2.