log2 1-lg3×log3 2-lg5

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log2 1-lg3×log3 2-lg5
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log2 1-lg3×log3 2-lg5
log2 1-lg3×log3 2-lg5

log2 1-lg3×log3 2-lg5
log₂1-lg3×log₃2-lg5
原式=0-(lg3×log₃2+lg5)
=0-﹙㏒₃3/㏒₃10 ×log₃2 + ㏒₃5/㏒₃10﹚
=0-[1/㏒₃10 (㏒₃2 +㏒₃5)]
=0-(1/㏒₃10 × ㏒₃10)
=0-1
=-1
我们这周的数学试卷上正好也有这一条,顺便帮你一下,一定要给分哦~

=0-log(10)3*log(3)2-log(10)5
=-log(10)3* [ log(10)2]/[log(10)3] -log(10)5
=-log(10)2-log(10)5
=-[log(10)2*5]
=-1
圆括号代表底数,注意!!!!