如果1/x-1/y=1,则分式y-x/x-xy-y=

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如果1/x-1/y=1,则分式y-x/x-xy-y=
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如果1/x-1/y=1,则分式y-x/x-xy-y=
如果1/x-1/y=1,则分式y-x/x-xy-y=

如果1/x-1/y=1,则分式y-x/x-xy-y=
如果1/x-1/y=1,则
分式y-x/x-xy-y
=(1/x-1/y)/(1/y-1/x-1)
=1/(-1-1)
=-1/2;
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(y-x)/(x-xy-y)
=(y-x+xy-xy)/(x-xy-y)
=-1-xy/(x-xy-y)
=-1-1/(1/y-1-1/x)
=-1+1/(1/x-1/y+1)
=-1+1/(1+1)
=-1+1/2
=-1/2


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(y-x)/(x-xy-y)
=(y-x+xy-xy)/(x-xy-y)
=-1-xy/(x-xy-y)
=-1-1/(1/y-1-1/x)
=-1+1/(1/x-1/y+1)
=-1+1/(1+1)
=-1+1/2
=-1/2


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如若满意,请点击[满意答案];如若您有不满意之处,请指出,我一定改正!
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