如图,在等腰梯形ABCD中AD‖BC,对角线AC⊥BD于O,AE⊥BC,DF⊥BC,垂足分别为E、F,AD=4,BC=8则AE+EF等于( )A9 B10 C11 D12
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/06 20:58:30
xTN@,B,)i^f/h?Hiv
mIDP R?$*;~ImE7Ι{ϽsJղ!p6>͋qScB3O!ꄰab`D6nK[6gYhM1s,pz:psӁsbң'VOD6pgB\ݎ"kf%m.PhamZ,(&q$CRh}EwL[nU00d@L-)e~i H `@vBRirܒR&5de˙Û; Hd!H[6mO9Px_ZQ=fAzB`dāF&oxS/8hHǐ7e@bF=s
DCVVV
y6y~&AB
Dvm2a"ȘR6af6NSo/[ULp"+?A&^LP]