(a+1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)=(a-1)[(a+1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)=[a^2-1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)=[(a^4-1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)=[(a^8-1)(a^8+1)(a^16+1)]/(a-1)=[(a^16-1)(a^16+1)]/(a-1)=(a^32-1)/(a-1)为什么要除

来源：学生作业帮助网 编辑：作业帮 时间：2024/06/10 15:43:38
(a+1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)=(a-1)[(a+1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)=[a^2-1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)=[(a^4-1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)=[(a^8-1)(a^8+1)(a^16+1)]/(a-1)=[(a^16-1)(a^16+1)]/(a-1)=(a^32-1)/(a-1)为什么要除
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(a+1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)=(a-1)[(a+1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)=[a^2-1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)=[(a^4-1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)=[(a^8-1)(a^8+1)(a^16+1)]/(a-1)=[(a^16-1)(a^16+1)]/(a-1)=(a^32-1)/(a-1)为什么要除
(a+1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)
=(a-1)[(a+1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)
=[a^2-1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)
=[(a^4-1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)
=[(a^8-1)(a^8+1)(a^16+1)]/(a-1)
=[(a^16-1)(a^16+1)]/(a-1)
=(a^32-1)/(a-1)
为什么要除以（a-1）

(a+1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)=(a-1)[(a+1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)=[a^2-1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)=[(a^4-1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)=[(a^8-1)(a^8+1)(a^16+1)]/(a-1)=[(a^16-1)(a^16+1)]/(a-1)=(a^32-1)/(a-1)为什么要除
因为乘了一个a-1,这样就可以连续用平方差公式,所以为了保持恒等,还要除以一个a-1

a(a-1)(a-2)(a-3)(a-4)因式分解 【1】a+a=a×a a= [ ]【2】a×a=a÷a a=[ ]【3】a×a=a－a a=[ ] [4]a－a=a＋a a=[ ] 计算[(a-1)/a*a-4*a+4]-[(a+2)/(a*a-2*a*a)]-4/a a+a+1+a+2+a+3+a+4+a+5+a+6+a+7.+a+2013+a+2014=? 幂的计算题1、a×a^2×a^3×a^4×a^52、a+2a+3a+4a+a×a^2×a^3×a^4 (1-16a×a×a×a)÷（4a×a+1)÷(2a+1)² (1-16a×a×a×a)÷(4a×a+1)÷(2a+1) a/a^2-4 a-1/a-2 a+2/a^2-4a+4 (a+1/a方-a+4/1-a方)/a方+2a-3/a+3 [(a/a-2)-(a/a+2)]÷4a/2-a,其中a=-1/2 [a^2-4/(a-3)(a+2)+(a+2)/a-3]除以a+1/a-3 [a-a/(a+1)]÷(a²-2a)/(a²-4)×(a+1)/(a²+4a+4) (a 1)(a 2)(a 3)(a (a+2)(a+1)-a(a-3) a=-1 求a-2a+3a-4a+5a-6a+...+99a-100a (a+4)(2a+1)(a-3) 化简：a^4-(1-a)(1+a)(1+a^2) (a-1)(a+1)(a^4+a^2+1)